[Okular-devel] Re: Question about XPS code

Albert Astals Cid aacid at kde.org
Sun May 8 20:19:59 CEST 2011


A Sunday, May 08, 2011, Pino Toscano va escriure:
> Hi,
> 
> Alle domenica 8 maggio 2011, Albert Astals Cid ha scritto:
> > i just saw we have this code
> > 
> > case 'q': // Quadratic bezier curve
> > 
> >     while (token.type == abtNumber)
> >     {
> >     
> >         QPointF point1 = getPointFromString(&token, isRelative,
> > 
> > currPos);
> > 
> >         QPointF point2 = getPointFromString(&token, isRelative,
> > 
> > currPos);
> > 
> >         path.quadTo(point2, point2);
> >     
> >     }
> >     break;
> > 
> > Brad/Jiri should the first point2 be point1?
> 
> According to the specs:
> - point1 is the control point
> - point2 is the end point
> so, according to the QPainterPath API, it should be
>   path.quadTo(point1, point2);
> as you suggests.

Done.

Albert


More information about the Okular-devel mailing list