[Okular-devel] Re: Question about XPS code
Pino Toscano
pino at kde.org
Sun May 8 19:34:17 CEST 2011
Hi,
Alle domenica 8 maggio 2011, Albert Astals Cid ha scritto:
> i just saw we have this code
>
> case 'q': // Quadratic bezier curve
> while (token.type == abtNumber)
> {
> QPointF point1 = getPointFromString(&token, isRelative,
> currPos);
> QPointF point2 = getPointFromString(&token, isRelative,
> currPos);
> path.quadTo(point2, point2);
> }
> break;
>
> Brad/Jiri should the first point2 be point1?
According to the specs:
- point1 is the control point
- point2 is the end point
so, according to the QPainterPath API, it should be
path.quadTo(point1, point2);
as you suggests.
--
Pino Toscano
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