D7034: Add callable type to PHP

[Matthijs Tijink]

mtijink added inline comments.

INLINE COMMENTS

> zhigalin wrote in duchain.cpp:751
> The problem arises then you return the **result** of calling `$i()` and the parser still think you're returning a callable

Ah ok, you're correct. But that's not due to a problem in this code, but problems in the `ExpressionVisitor`: it skips most operators, such that the resulting type is that of the last appearing variable/literal. Thus, it applies the type of `$i` instead of the result of calling the function.

For example, `function foo() { $i = function () {}; return $i(); }` yields type `void () foo ()`, which also is incorrect.

REPOSITORY
  R52 KDevelop: PHP Support

REVISION DETAIL
  https://phabricator.kde.org/D7034

To: mtijink, #kdevelop, zhigalin
Cc: zhigalin, kdevelop-devel
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