[Kde-pim] Review Request: Remove all the signature blocks.
Jaime Torres
jtamate at gmail.com
Thu Mar 26 18:43:18 GMT 2009
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This is an automatically generated e-mail. To reply, visit:
http://reviewboard.kde.org/r/403/
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(Updated 2009-03-26 11:43:18.319312)
Review request for KDE PIM.
Changes
-------
I hope this is the good one.
Summary
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Remove all the signature blocks.
The algorithm is:
Look for the prefixes before the "-- " marks (i.e. the text before it in the line).
foreach line, if the line contains "-- ", start to delete lines until the prefix changes.
(it should also work with c code if the -- is not followed by a space).
This addresses bug 72316.
https://bugs.kde.org/show_bug.cgi?id=72316
Diffs (updated)
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/trunk/KDE/kdepim/kmail/kmmessage.cpp 944557
Diff: http://reviewboard.kde.org/r/403/diff
Testing (updated)
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#include <QtCore/QtCore>
#include <iostream>
using namespace std;
/**
remove the Signature Blocks (SB) from prefix+"-- (end of line)" until a
line that
* does not starts with prefix or
* starts with prefix+(any substring of prefix)
*/
static QString
stripSignature ( const QString & msg, bool clearSigned )
{
QRegExp SBDelimiterSearch = clearSigned ? QRegExp( "--\\s?\n" ) :
QRegExp( "-- \n" );
QString res = msg;
QString commonPrefixChars = QString( '>' );
QString commonPrefixCharsTmp;
QString prefix; // the current prefix
QString line; // the line to check if is part of the SB
int posDeletingStart = -1;
int posNewLine = -1;
int posSignatureBlock = -1;
// Look for prefixes, to guess the used reply prefixes
// Only usefull for the case where the actual prefix is empty
while ( (posSignatureBlock = res.indexOf( SBDelimiterSearch,
posSignatureBlock + 1 ))
>= 0 )
{
// Look back for the line begining
posDeletingStart = res.lastIndexOf( '\n', posSignatureBlock ) + 1;
// The prefix before "-- "$, for example, in ">> -- " is ">> "
prefix = res.mid( posDeletingStart, posSignatureBlock - posDeletingStart );
// The regular expresion to look for prefix change will not contain " "
for ( int i = 0; i < prefix.size(); i++ )
{
if ( prefix[i] != ' ' && !commonPrefixChars.contains( prefix[i] ) )
commonPrefixChars.append( prefix[i] );
}
}
// The regular expresion to look for prefix change
QRegExp CommonReplySearch =
QRegExp( QString( '[' ) + commonPrefixChars + QString( ']' ) );
// While there are SB delimiters
while ( (posSignatureBlock = res.indexOf( SBDelimiterSearch )) >= 0 )
{
// Look back for the line begining
posDeletingStart = res.lastIndexOf( '\n', posSignatureBlock ) + 1;
// The prefix before "-- "$, for example, in ">> -- " is ">> "
prefix = res.mid( posDeletingStart, posSignatureBlock - posDeletingStart );
posNewLine = res.indexOf( '\n', posSignatureBlock ) + 1;
// now go to the end of the SB
while ( posNewLine < res.size() && posNewLine > 0 )
{
// check when the SB ends
line = res.mid( posNewLine, res.indexOf( '\n', posNewLine ) -
posNewLine );
// * does not starts with prefix or
// * starts with prefix+(any substring of prefix)
if ( (prefix.isEmpty() && line.indexOf( CommonReplySearch ) < 0) ||
(!prefix.isEmpty() && line.startsWith( prefix ) && !prefix.contains(
line.mid( prefix.size(), 1 ) )) )
{
posNewLine = res.indexOf( '\n', posNewLine ) + 1;
}
else
break;
}
// remove the SB or truncate when is the last SB
if ( posNewLine > 0 )
res.remove( posDeletingStart, posNewLine - posDeletingStart );
else
res.truncate( posDeletingStart );
}
return res;
}
int
main ( int argc, const char *argv[] )
{
QStringList tests;
tests << "text1\n-- \nSignature Block1\nSignature Block1\n\n"
"> text2\n> -- \n> Signature Block 2\n> Signature Block 2\n"
">> text3 -- not a signature block\n>> text3\n"
">>> text4\n> -- \n> Signature Block 4\n> Signature Block 4\n"
">>-------------\n>>-- text5 --\n>>-------------------\n>> -- \n>>
Signature Block 5\n"
"text6\n-- \nSignature Block 6";
tests << "text1\n"
"> text2\n"
">> text3 -- not a signature block\n>> text3\n"
">>> text4\n"
">>-------------\n>>-- text5 --\n>>-------------------\n"
"text6\n";
tests << "text1\n-- \nSignature Block1\nSignature Block1\n\n"
">text2\n>-- \n>Signature Block 2\n>Signature Block 2\n"
"> >text3\n> >text3\n> >-- \n>>Signature Block 3\n> >Signature Block 3\n"
">text4\n>-- \n>Signature Block 4\n>Signature Block 4\n"
"text5\n-- \nSignature Block 5";
tests << "text1\n"
">text2\n"
">>Signature Block 3\n> >Signature Block 3\n"
">text4\n"
"text5\n";
tests << "Text 1\n-- \nFirst sign\n\n\n> From: bla\n"
"> Texto 2\n\n> Aqui algo de texto.\n\n>> --\n>> Not Signature
Block 2\n\n> Adios\n"
"\n>> Texto 3\n\n>> --\n>> Not Signature block 3\n";
tests << "Text 1\n> From: bla\n"
"> Texto 2\n\n> Aqui algo de texto.\n\n>> --\n>> Not Signature
Block 2\n\n> Adios\n"
"\n>> Texto 3\n\n>> --\n>> Not Signature block 3\n";
tests << "-- \n-- ACME, Inc\n-- Joe User\n-- PHB\n-- Tel.: 555 1234\n--";
tests << "";
QString t4, t5;
for ( int i = 0; i < 100; i++ )
{
t4.append( tests[4] );
t5.append( tests[5] );
}
tests << t4 << t5;
QTime time = QTime::currentTime();
for ( int j = 0; j < 500; j++ )
{
for ( int i = 0; i < 5; i++ )
{
QString res = stripSignature( tests[i * 2], 0 );
// cout << "result:\n" << res.toStdString() << endl <<
"expected:\n" << tests[i*2+1].toStdString() << endl;
assert( res == tests[i * 2 + 1] );
}
}
cout << time.elapsed() << endl;
}
Thanks,
Jaime
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