implicit QChar constructors

Christopher Eineke kde-optimize@mail.kde.org
Thu, 23 Jan 2003 05:23:04 -0500


Oswald Buddenhagen wrote:
>>I wonder if "bool already;" defaults to zero
>i would not talk about "default" in this case ...

Ok, initialized. But I kinda tried to make a pun with "bool already". I
think I(t) failed ;-)

>>(its a fifty-fifty situation. Who does accept bets?)
>
> i do. :) a bool is usually an int and anything non-zero is true. so your
> chances are something like 1:2^32 on 32-bit platforms ...

So it's still a fifty-fifty situation, just with unbalanced chances....

Don't beat me! X)
-- 
Chris