implicit QChar constructors

Oswald Buddenhagen kde-optimize@mail.kde.org
Thu, 23 Jan 2003 10:46:51 +0100


On Thu, Jan 23, 2003 at 04:27:31AM -0500, Christopher Eineke wrote:
> I wonder if "bool already;" defaults to zero
>
i would not talk about "default" in this case ...

> (its a fifty-fifty situation. Who does accept bets?)
> 
i do. :) a bool is usually an int and anything non-zero is true. so your
chances are something like 1:2^32 on 32-bit platforms ...

greetings

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