how to figure out what options are supported, was Re: Odd crash with MySQL Embedded 5.1.28
Dan Nelson
dnelson at allantgroup.com
Fri Sep 26 23:15:29 CEST 2008
In the last episode (Sep 26), Ian Monroe said:
> On Fri, Sep 26, 2008 at 1:55 PM, Ian Monroe <ian at monroe.nu> wrote:
> > On Fri, Sep 26, 2008 at 9:37 AM, Ian Monroe <ian at monroe.nu> wrote:
> >> So we're using MySQL Embedded in Amarok, it works fine for most of us
> >> that use 5.1, including myself. However the following backtrace is
> >> from the second person to have this issue. Its repeatable, happens at
> >> startup.
> >>
> >> Is there something about how their MySQL is setup on their system that
> >> could cause such a crash?
> > [snip]
> >> mysql_library_init(num_elements, server_options, server_groups);
> >> m_db = mysql_init(NULL); // <- crash happens HERE
> >
> > So we did figure out that mysql_library_init is returning 1, which
> > explains why mysql_init is crashing.
> >
> > But how do we figure out what exactly the '1' means? Any clues?
>
> We figured it out: we had --skip-innodb, which crashed anyone who
> didn't have Innodb support built.
>
> Is there any way we could have it add --skip-innodb if and only if
> Innodb support is present? I can't find a mysql_* function that
> describes server functionality. A compile time option would work as
> well I suppose, since we're currently statically linking.
You want --loose-skip-innodb.
http://dev.mysql.com/doc/refman/5.0/en/command-line-options.html
If an option is prefixed by --loose, a program does not exit with an
error if it does not recognize the option, but instead issues only a
warning:
$ mysql --loose-no-such-option
mysql: WARNING: unknown option '--no-such-option'
--
Dan Nelson
dnelson at allantgroup.com
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