c++ syntax highlighting
Andreas Pakulat
apaku at gmx.de
Mon May 14 14:24:54 BST 2007
On 14.05.07 15:15:10, hg wrote:
> in c++-project if I type a preprocessor construct like
>
> #if 0
> some grayed code
> #else
> some black colored code
> #endif
>
> the first part behind the '#if 0' is correctly displayed in gray cause it's
> not in use.
> But if I change the statement into "#if 1' both parts are displayed as beeing
> active in black color:
>
> #if 1
> some black colored code
> #else
> some black colored code
> #endif
>
> Shouldn't now the else block be displayed in inactive gray color?
I doubt kate's highlighter is able to parse this, but feel free to file
a bugreport against kate. KDevelop doesn't do any syntax highlighting in
KDevelop3.
Andreas
--
Give your very best today. Heaven knows it's little enough.
More information about the KDevelop
mailing list