Review Request 110638: Fix every compound assignment operator being regognized as "+="

[Sven Brauch]

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http://git.reviewboard.kde.org/r/110638/
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Review request for KDevelop and Milian Wolff.


Description
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It was noticed that before this change, all operators in statements
such as
    Foo a, b;
    a ^= b;
    a &= b;
etc. will be displayed as uses of Foo::operator+=(), which is obviously
wrong. The reason for this was some rather curious code, which just
treated every of these operators as "Token_assign" in the lexer,
and some other code which treated each "Token_assign" as "+=" in the
analyzer. To fix the issue, this had to be sorted out.
    - Token_assign doesn't make sense anyways, since assignments are
    represented as "=". So, remove the token completely.
    - Instead of lexing every compound assignment operator as "Assign",
    yield different token types for each.
    - In the code which handles the operators, change the function from
    using its own list of tokenkind -- tokenText mapping to use the
    official one.
Also included is a unit test for the fix.


Diffs
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  languages/cpp/cppduchain/builtinoperators.cpp 0def471 
  languages/cpp/cppduchain/expressionvisitor.cpp 3db7be0 
  languages/cpp/cppduchain/tests/test_duchain.h ebc1ee8 
  languages/cpp/cppduchain/tests/test_duchain.cpp f83416b 
  languages/cpp/parser/lexer.cpp b39387a 
  languages/cpp/parser/parser.cpp 41f00ec 
  languages/cpp/parser/tokens.h dd173a3 
  languages/cpp/parser/tokens.cpp 9086a8e 

Diff: http://git.reviewboard.kde.org/r/110638/diff/


Testing
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Thanks,

Sven Brauch

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