[Bug 272750] Update Argentina holidays rule file

[dv5a at dc.uba.ar]

https://bugs.kde.org/show_bug.cgi?id=272750





--- Comment #7 from  <dv5a dc uba ar>  2012-01-05 21:43:31 ---
Thanks!!

It is a little tricky.  "Dia de San Martin" is always 3rd Monday of august
(every year), but in 2011 it was approved a law that only that year it will be
on 4th Monday of august. 

I am doing some date arithmetic there. (year == 2011) results in 1 for 2011 and
0 otherwise.

So, For year==2011 =>

(third + (year == 2011)) monday in august
(third + (2011 == 2011)) monday in august
(third + (1)) monday in august
(third + 1) monday in august
fourth monday in august

And for any other year =>

(third + (year == 2011)) monday in august
(third + (0)) monday in august
(third + 0) monday in august
third monday in august

Is there another way to express this condition?
Should I comment the logic used in the holidays file?

Thanks again

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