[Kde-perl] How does shift->SUPER::NEW works?
Rafael Beccar
rafabeccar at speedy.com.ar
Thu May 27 02:14:51 CEST 2004
Hi,
I'm having a hard time trying to properly use the constructor built by
PerlQt Designer.
I think my problem is that I don't understand how the following line
works:
shift->SUPER::NEW(@_[0..3]);
What does this line do with the parameters passed to the constructor and
how do I get them once the line was executed?
If do this:
my $arg = $_[1];
shift->SUPER::NEW(@_[0..3]);
I get the parameter I want in the $arg variable, but I think this is not
the best way to do it as the first line is removed every time I run
puic.
So, any comment that guides me towards the right answer would be really
appreciated.
Regards,
Rafael
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