New shared pointer - revision 2

[Frerich Raabe]

On Saturday 10 September 2005 02:53, Thiago Macieira wrote:
> The code path is this:

[..]
> Suppose d->ref == 2.

[..]

Yes, you are right of course, I don't know what I was thinking. Maybe it's 
true that I should not do such things in the middle of the night. The copy 
constructor should simply be

template <class T>
KSharedPtr<T>::KSharedPtr( const KSharedPtr<T> &other )
{
	KSharedData *x = other.d;
	x = qAtomicSetPtr( &d, x );
	d->ref.ref();
}

and the assignment operator from T* should be like you outlined in one of the 
other mails.

- Frerich
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