[PATCH] Re: What not to be doing - syscall()

Frans Englich frans.englich at telia.com
Wed Dec 24 17:59:35 GMT 2003

On Tuesday 23 December 2003 21:13, Thiago Macieira wrote:
> Frans Englich wrote:
> >+  const char *user = KUser().loginName().latin1();
> I have a problem with that, in your last patch. The QString object the from
> which you're getting the Latin1 is a temporary object and will be destroyed
> shortly thereafter, so the variable will point to a deallocated pointer.
> Use a QCString there for user or keep the QString around.

Ok, second try. This time no dangling pointer, but latin1 is kept - I let you 
fight over that ;-)
But what Lukás comments could be valid, what does the posix/de-facto(or 
whatever in charge) say about unix logins? Is everything but ascii 

(the other two is unchanged)



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