[Digikam-devel] Re: Logic error

[Marcel Wiesweg]

> But don't you have to declare it "virtual" again in all derived classes,
> although the base class already defined it like this?
> 

Yes, a method is always virtual if declared in the base class, in the derived 
class the keyword is cosmetic. Same source as above:

"Note: in a derived class, if your base class has a virtual destructor, your 
own destructor is automatically virtual. You might need an explicit destructor 
for other reasons, but there's no need to redeclare a destructor simply to 
make sure it is virtual. No matter whether you declare it with the virtual 
keyword, declare it without the virtual keyword, or don't declare it at all, 
it's still virtual."

Marcel