Yes... , i don't know anything about flowcode, but the rotate instruction in the pic is always done through carry, then you should clear Status,C bit (carry) just before the rotate.<br>But using high-level languages you never can be sure about what is really happening, there are in some languages the rotate-with-carry and rotate-without-carry instructions, but i don't know flowcode.<br>
<br>Anyway you can try clearing status,c bit just before rotating, perhaps this works.<br><br><div class="gmail_quote">2009/9/20 Matthew Ayres <span dir="ltr"><<a href="mailto:solar.granulation@gmail.com">solar.granulation@gmail.com</a>></span><br>
<blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;"><br><br><div class="gmail_quote">On Sun, Sep 20, 2009 at 6:31 PM, P Zoltan <span dir="ltr"><<a href="mailto:zoltan.padrah@gmail.com" target="_blank">zoltan.padrah@gmail.com</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;">
<div>On Wed, 16 Sep 2009 16:56:55 +0200, Matthew Ayres<br>
<<a href="mailto:solar.granulation@gmail.com" target="_blank">solar.granulation@gmail.com</a>> wrote:<br>
<br>
> Using flowcode I'm performing a right-rotation on variable x on a P16F84.<br>
<br>
<br>
</div> How looks the code exactly? And in what is it written (C, ASM, flowcode)?<br>
<br>
I can think to some intruction "shift right with carry", which takes the<br>
value from the carry bit and places it in the most significant bit of the<br>
register.</blockquote><div><br>Flowcode.<br><br>I have at least determined that it's some kind of 6-bit value. <br></div></div>
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