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<DIV><FONT face=Arial size=2>hi everybody ......</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>i used the kprocess class to run and keep track of
a child process in my application so i used the "recievedstderr" signal to
recieve the output error in a certain buffer and connected it to a certain slot
that accumulates this buffer in a string that i will use to create a messagebox
.....also i used the "processexited" signal to do some actions when this process
exits and i tried it and everything works perfectly but only for the 1st
time::::</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>the child process is created when i click a certain
button which i have connected it to certain slot that make
this.............</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>the problem:</FONT></DIV>
<DIV><FONT face=Arial size=2>when the process exits for the 1st time the slot
that is connected to the "processexited" signal is called one time ..... and
then when it exits in the second time the slot is called two times and in the
third time the slot is called three times and so on till
infenity........................that means that the signal processexited
accumulates with that of the last process.........!!!!!!!!!!!!!!!!!</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>i dont know why this senario happens : if anyone
can interpret or solve this problem i will be glad ...</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>any help is appreciated.</FONT></DIV>
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