<table><tr><td style="">thiago added a comment.
</td><a style="text-decoration: none; padding: 4px 8px; margin: 0 8px 8px; float: right; color: #464C5C; font-weight: bold; border-radius: 3px; background-color: #F7F7F9; background-image: linear-gradient(to bottom,#fff,#f1f0f1); display: inline-block; border: 1px solid rgba(71,87,120,.2);" href="https://phabricator.kde.org/D14302">View Revision</a></tr></table><br /><div><div><p>Quickly checking on openSUSE Tumbleweed</p>
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<div style="font-style: normal;
padding-bottom: 4px;">In <a href="https://phabricator.kde.org/D14302#297185" style="background-color: #e7e7e7;
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<p>QDeadlineTimer timer(qMax(timeout, -1)); // QDT only takes -1 as "forever"</p>
<p>passes the result of qMax() to QDeadlineTimer's constructor. That constructor receives a quint64. Since qMax() is a template:</p></div>
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<p>The constructor takes a qint64, not a quint64.</p>
<blockquote style="border-left: 3px solid #a7b5bf; color: #464c5c; font-style: italic; margin: 4px 0 12px 0; padding: 4px 12px; background-color: #f8f9fc;"><p>inline const T &qMax(const T &a, const T &b) { return (a < b) ? b : a; }</p>
<p>it will use the type of the assigned variable (quint64 in this case) as T and casting -1 to INT64_MAX. Changing the line to:</p></blockquote>
<p>Again, incorrect. It will use the type T, which must be the same for both arguments. The timeout parameter is int and the -1 literal is int. So the comparison is performed in int, which should return 0.</p></div></div><br /><div><strong>REPOSITORY</strong><div><div>R271 KDBusAddons</div></div></div><br /><div><strong>REVISION DETAIL</strong><div><a href="https://phabricator.kde.org/D14302">https://phabricator.kde.org/D14302</a></div></div><br /><div><strong>To: </strong>jtamate, dfaure, Frameworks, thiago<br /><strong>Cc: </strong>lvsouza, kde-frameworks-devel, michaelh, ngraham, bruns<br /></div>